分布计算，分布计算36除以3与3的积商是多少这道题怎么做分布计算

来源：整理时间：2023-10-17 12:34:56 编辑：智能门户手机版

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1，分布计算36除以3与3的积商是多少这道题怎么做分布计算
2，正态分布常用公式
3，怎么用科学计算器算正态分布值
4，如何使用韦伯分布函数
5，如何求概率分布
6，求概率分布

1，分布计算36除以3与3的积商是多少这道题怎么做分布计算

36/3*3=36/9=4

（880-36x15）÷17=20

分布计算36除以3与3的积商是多少这道题怎么做分布计算

2，正态分布常用公式

你这里a>0，所以P因为P{|x|≥a}=P{x≥a}+P{x≤-a}，标准正态分布P{x≥a}=P{x≤-a}，所以P{x≥a}=P{|x|≥a}/2

自然对数的底，是（1+1/n）^n在n趋向正无穷时的极限，其值约等于2.718281828。计算的时候直接代入就行了。一般数学软件里面都可以直接用。至于为什么正态分布公式里会有e存在，我想是在计算分布的时候总体越大越精确，所以会取一个n趋向正无穷的数，那么出现了上面的极限，就用e来代替了。

正态分布常用公式

3，怎么用科学计算器算正态分布值

计算方法：(1) P（Z≥0.3）=0.3821 a 进入单一变量统计模b 进入正态分布模式 shift 1 7 3 0.3 ） =(2) p(－0.3≤Z≤0.3)=0.2358 a 进入单一变量统计模式 Mode 3 1 AC b 进入正态分布模式 shift 1 7 3 0.3 ）－ shift 1 7 3 （－）0.3 ）=

计算方法：(1)p（z≥0.3）a进入单一变量统计模式mode31acb进入正态分布模式shift1730.3）=(2)p(－0.3≤z≤0.3)=0.2358a进入单一变量统计模式mode31acb进入正态分布模式shift1730.3）－shift173（－）0.3）=

怎么用科学计算器算正态分布值

4，如何使用韦伯分布函数

weibull(x,alpha,beta,cumulative)x 参数值。alpha 分布参数。beta 分布参数。cumulative 指明函数的形式。说明如果x、alpha 或 beta 为非数值型，函数 weibull 返回错误值 #value!。如果x < 0，函数 weibull 返回错误值 #num!。如果alpha ≤ 0 或 beta ≤ 0，函数 weibull 返回错误值 #num!。韦伯累积分布函数的计算公式如下：韦伯概率密度函数的计算公式如下：当alpha = 1，函数 weibull 返回指数分布：示例如果您将示例复制到空白工作表中，可能会更易于理解该示例。操作方法创建空白工作簿或工作表。请在“帮助”主题中选取示例。不要选取行或列标题。从帮助中选取示例。按ctrl+c。在工作表中，选中单元格 a1，再按 ctrl+v。若要在查看结果和查看返回结果的公式之间切换，请按 ctrl+`（重音符），或在“工具”菜单上，指向“公式审核”，再单击“公式审核模式”。 1234ab数据说明105计算函数的数值20α 分布参数100β 分布参数公式说明（结果）=weibull(a2,a3,a4,true)在上述条件下使用韦伯累积分布函数的结果 (0.929581)=weibull(a2,a3,a4,false)在上述条件下使用韦伯概率密度函数的结果 (0.035589)

密度函数： x≤0时，p(x)=0; x﹥0时，p(x)=aλx^(a-1)exp(-λx^a). 累计分布函数： x≤0时，F(x)=0； x＞0时，F(x)=∫aλt^(a-1)exp(-λt^a)dt 积分(0,x) =-∫exp(-λt^a)d(-λt^a) =- exp(-λt^a) t从0到x =1- exp(-λx^a) 结论：x≤0时，F(x)=0； x＞0时，F(x)=1- exp(-λx^a)

5，如何求概率分布

求出概率分布函数然后在整个区间上积分

好，我试着描述了一下从1 -5 的分布几率以及变化:in 1d6 case, the result is as following:the probability of getting a 1 is 0.17the probability of getting a 2 is 0.17the probability of getting a 3 is 0.17the probability of getting a 4 is 0.17the probability of getting a 5 is 0.17the probability of getting a 6 is 0.17in 2d6 case, the result is as following:the probability of getting a 2 is 0.03the probability of getting a 3 is 0.06the probability of getting a 4 is 0.08the probability of getting a 5 is 0.11the probability of getting a 6 is 0.14the probability of getting a 7 is 0.17the probability of getting a 8 is 0.14the probability of getting a 9 is 0.11the probability of getting a 10 is 0.08the probability of getting a 11 is 0.06the probability of getting a 12 is 0.03in 3d6 case, the result is as following:the probability of getting a 3 is 0.00the probability of getting a 4 is 0.01the probability of getting a 5 is 0.03the probability of getting a 6 is 0.05the probability of getting a 7 is 0.07the probability of getting a 8 is 0.10the probability of getting a 9 is 0.12the probability of getting a 10 is 0.12the probability of getting a 11 is 0.13the probability of getting a 12 is 0.12the probability of getting a 13 is 0.10the probability of getting a 14 is 0.07the probability of getting a 15 is 0.05the probability of getting a 16 is 0.03the probability of getting a 17 is 0.01the probability of getting a 18 is 0.00in 4d6 case, the result is as following:the probability of getting a 4 is 0.00the probability of getting a 5 is 0.00the probability of getting a 6 is 0.01the probability of getting a 7 is 0.02the probability of getting a 8 is 0.03the probability of getting a 9 is 0.04the probability of getting a 10 is 0.06the probability of getting a 11 is 0.08the probability of getting a 12 is 0.10the probability of getting a 13 is 0.11the probability of getting a 14 is 0.11the probability of getting a 15 is 0.11the probability of getting a 16 is 0.10the probability of getting a 17 is 0.08the probability of getting a 18 is 0.06the probability of getting a 19 is 0.04the probability of getting a 20 is 0.03the probability of getting a 21 is 0.02the probability of getting a 22 is 0.01the probability of getting a 23 is 0.00the probability of getting a 24 is 0.00in 5d6 case, the result is as following:the probability of getting a 5 is 0.00the probability of getting a 6 is 0.00the probability of getting a 7 is 0.00the probability of getting a 8 is 0.00the probability of getting a 9 is 0.01the probability of getting a 10 is 0.02the probability of getting a 11 is 0.03the probability of getting a 12 is 0.04the probability of getting a 13 is 0.05the probability of getting a 14 is 0.07the probability of getting a 15 is 0.08the probability of getting a 16 is 0.09the probability of getting a 17 is 0.10the probability of getting a 18 is 0.10the probability of getting a 19 is 0.09the probability of getting a 20 is 0.08the probability of getting a 21 is 0.07the probability of getting a 22 is 0.05the probability of getting a 23 is 0.04the probability of getting a 24 is 0.03the probability of getting a 25 is 0.02the probability of getting a 26 is 0.01the probability of getting a 27 is 0.00the probability of getting a 28 is 0.00the probability of getting a 29 is 0.00the probability of getting a 30 is 0.006d6上面的东西都和武器无缘了。。。不是长期拥有的东西也没必要去在意它到底出多少点吧？大概规律就是中间多两边少，成钟型分布。下面是程序：/* * to change this template, choose tools | templates * and open the template in the editor. */package diceandprobability;import java.text.decimalformat;import java.text.numberformat;import java.util.arraylist;import java.util.iterator;import java.util.list;import java.util.random;/** * * @author yichuan */public class main /** * @param args the command line arguments */ public static void main(string[] args) final int total_roll = 1000000; final int num_dice = 2; final string prompt = "in " + num_dice + "d6 case, the result is as following:\n"; random ran = new random(); list result = new arraylist(); int num = 0; int count = 0; for(int i = 0; i < total_roll; i++){ for(int j = 0; j < num_dice; j ++){ num += ran.nextint(6)+1; } result.add(num); num = 0; } system.out.println(prompt); for(int i = num_dice; i <= num_dice * 6; i ++){ iterator iter = result.iterator(); while(iter.hasnext()){ if (iter.next() == i){ count ++; } } double amount = count / (total_roll + 0.0); numberformat format = new decimalformat("#0.00000"); system.out.println("the probability of getting a " + i + " is " + format.format(amount)); count = 0; } } }